Ali is considering purchasing a common stock that pays an annual dividend of $8.90 per share. If he purchases 450 shares for $75
1 answer:
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Answer:
The correct option is (B)
(B) x-y = 6 , 3x+4y = 4
Step-by-step explanation:
As we can see in the graph given below, both lines intersect at (4, -2), which should be the solution of given equations:
Find the values of x and y for (B);
x - y = 6 ⇒ (i)
3x + 4y = 4 ⇒ (ii)
Lets consider equation (i)
x - y = 6
x = 6 + y
Substitute in equation (ii)
3(6+y) + 4y = 4
18 + 3y + 4y = 4
7y = -14
y = -2
Substitute in equation (i)
x - (-2) = 6
x + 2 = 6
x = 6 - 2
x = 4
As solution of part C is also (4, -2), it represents the graph
You can also find the (x, y) for other options the similar way, which will show you they don't have the same value
When you have a bunch like this, I find it easiest to graph them.
The numbers of real solutions are ...
2
0
2
1
I know you know how to use Desmos to graph these. You can also write a little spreadsheet program to compute the discriminant b^2 -4ac, or do it the hard way.
1^2 -4(-3)(12) = 145 . . . positive, so 2 solutions
(-6)^2 -4(2)(5) = -4 . . .. negative, so 0 solutions
7^2 -4(1)(-11) = 93 . . . .. positive, so 2 solutions
(-8)^2 -4(-1)(-16) = 0 . .. zero, so 1 solution
The numbers of real solutions are ...
2
0
2
1
I know you know how to use Desmos to graph these. You can also write a little spreadsheet program to compute the discriminant b^2 -4ac, or do it the hard way.
1^2 -4(-3)(12) = 145 . . . positive, so 2 solutions
(-6)^2 -4(2)(5) = -4 . . .. negative, so 0 solutions
7^2 -4(1)(-11) = 93 . . . .. positive, so 2 solutions
(-8)^2 -4(-1)(-16) = 0 . .. zero, so 1 solution