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3 years ago

The graph shows the function f(x).

Mathematics

2 answers:

Artist 52 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

What we have to do here is to select a point from the graph

We can select the point (-8,1)

What this simply mean is that when x = -8, y = 1

Now, let us take a look at the second third option

f(-8) will be the cube root of -(-8) , with 1 subtracted from it

The cube root of 8 is simply 2, subtracting 1 from it will yield 1

so that makes the point (-8,1) valid

kifflom [539]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

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