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Bas_tet [7]
2 years ago
13

GIVING BRAINLIEST BRAINLIEST!!!! Easy mathhh

Mathematics
2 answers:
Serggg [28]2 years ago
6 0

Answer:

is D i had this on my math test

Step-by-step explanation:

Alik [6]2 years ago
3 0

Answer:

the area is 20 units

Step-by-step explanation:

if you plot the points then draw the rectangle then you count the amount on each side and multiply 4 times 5

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In base $10$, the number $2013$ ends in the digit $3$. in base $9$, on the other hand, the same number is written as $(2676)_{9}
skelet666 [1.2K]
Note that

2013_{10}=2(10)^3+1(10)^1+3(10)^0

so that

\dfrac{2013}{10}=200+1+\dfrac3{10}

i.e. the remainder upon dividing 2013 (in base 10) by 3 is 3. The point is that any base-b representation of 2013_{10} will end in the digit 3 whenever division of 2013 by b leaves a remainder of 3.

First, we require that b\ge4, because any smaller base simply won't have 3 as a possible digit.

Second, we clearly can't have b\ge2014, because any value of b beyond that point will have 2013 as its first digit. That is, in base 2014, for instance, if we separate the digits of numbers by colons, we would simply have 2013_{10}=0:0:0:2013_{2014} (the 0s aren't necessary here, but only used for emphasizing that 2013 would be its own digit, regardless of how we represent digits outside of 0-9).

Third, we can't have b=2013 because 2013 divides itself and has no remainder. That is, 2013_{10}=10_{2013}.

So we've reduced the possible domain of solutions from all positive integers to just those lying within 4\le b\le2012.

Now, in terms of modular arithmetic, we're essentially solving the following equivalence for b:

2013\equiv3\pmod b

which, if you're not familiar with the notation or notion of modular arithmetic, means exactly "2013 gives a remainder of 3 when divided by b". It's equivalent to saying "there exists an integer n such that 2013=bn+3.

From this equation, we have 2010=bn. Now, we know both b,n must be integers, so we need only find the factors of 2010. These are

1, 2, 3, 5, 6, 10, 15, 30, 67, 134, 201, 335, 402, 670, 1005, 2010

So we have 16 total possible choices for b,n. But we're omitting 1, 2, and 3 from the solution set, which means there are 13 base-b representations of the base-10 number 2013_{10} such that the last digit 2013_b is 3. They are

2013_{10}=31,023_5
2013_{10}=13,153_6
2013_{10}=2013_{10}
2013_{10}=8:14:3_{15}
2013_{10}=2:7:3_{30}
2013_{10}=30:3_{67}
2013_{10}=15:3_{134}
2013_{10}=10:3_{201}
2013_{10}=6:3_{335}
2013_{10}=5:3_{402}
2013_{10}=3:3_{670}
2013_{10}=2:3_{1005}
2013_{10}=1:3_{2010}

- - -

Added a link to some code that verifies this solution. In case you're not familiar with Mathematica or the Wolfram Language, in pseudocode we are doing:

1. Start with a placeholder list called "numbers", consisting of all 0s, of length 2010. We know 4\le b\le2013, which contains 2010 possible integers.
2. Iterate over b:
2a. Start with b=4.
2b. Ensure b doesn't exceed 2013.
2c. After each iteration, increment b by 1; in other words, after each step, increase b by 1 and use this as a new value of b.
2d. Check if the last digit of the base-b representation of 2013 ends is a 3. In the WL, IntegerDigits[x, n] gives a list of the digits of x in base-n. We only want the last digit, so we take Last of that. Then we check the criterion that this value is exactly 3 (===).
2d1. If the last digit is 3, set the (b-3)-th element of "numbers" to be a list consisting of the base b and the list of digits of 2013 in that base.
2d2. Otherwise, do nothing, so that the (b-3)-th element of "numbers" remains a 0.
3. When we're done with that, remove all cases of 0 from "numbers" (DeleteCases). Call this cleaned list, "results".
4. Display "results" in Grid form.
5. Check the length of "results".
7 0
3 years ago
What is the first step in evaluating this expression?
Rufina [12.5K]
A.

PEMDAS

Parenthesis always comes first, then exponents, multiplication and division, adding and subtracting
7 0
3 years ago
Read 2 more answers
A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a
miss Akunina [59]

Answer:

18 bags

with 90/18 = 5 apples

and 72/18 = 4 oranges

in each bag

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is equivalent to 7(x - 3)?
Murljashka [212]
Simple....

What is equivalent to 7(x-3)?

Distributing....

7*x=7x

7*-3=-21

7x-21

Thus, your answer.
3 0
3 years ago
Read 2 more answers
Does the amount of points on the line of best fit matter?
stealth61 [152]
No there just has to be one or two on the line
6 0
3 years ago
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