Please help me!!!!!!!

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

4 0

Answer:

1 1/2

Step-by-step explanation:

Took the same thing

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Is my answer correct? if not please correct me

elena-s [515]

Using the given equation y-3 = 3/4(x+2)

Give Y a value and then solve for x:

If y = 0 the equation is now:

0 -3 = 3/4(x+2)

Solve for x:

-3 = 3/4x + 1.5

-4.5 = 3/4x

x = -4.5 / 3/4

x = -6

So the first point would be (-6,0)

Now make x 0 and solve for y:

y -3 = 3/4(0+2)

y-3 = 0 + 1.5

y = 4.5

So the 2nd point would be (0,4.5)

You are close, but the dot you have on y=4, needs to be moved up to 4.5.

8 0

3 years ago

How do you do this question?

Lisa [10]

Answer:

Correct integral, third graph

Step-by-step explanation:

Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.

Given : ∫ tan²(θ)sec²(θ)dθ

Applying u-substitution : u = tan(θ),

=> ∫ u²du

Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1

Substitute back u = tan(θ) : tan^2+1(θ)/2+1

Simplify : 1/3tan³(θ)

Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.