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xxMikexx [17]
3 years ago
7

Are the graphs of the lines in the pair parallel ? Explain.

Mathematics
1 answer:
Julli [10]3 years ago
3 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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a) Effective annual rate: 18.6%

b) Effective annual rate: 20.27%

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d) Effective annual rate: 20.44%

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The effective annual interest rate, if it is not compounded continuously, is given by the formula

I=C(1+\frac{r}{n})^{nt}-C

where

<em>C = Amount of the credit granted </em>

<em>r = nominal interest per year </em>

<em>n = compounding frequency </em>

<em>t = the length of time the interest is applied. In this case, 1 year. </em>

In the special case the interest rate is compounded continuously, the interest is given by

I=Ce^{rt}-C

(a)  Annually

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The effective annual rate is 18.6%

(b) Monthly

<em>There are 12 months in a year </em>

I=C(1+\frac{0.186}{12})^{12}-C=C(1.2027)-C=C(0.2027)

The effective annual rate is 20.27%

(c) Daily

<em>There are 365 days in a year </em>

I=C(1+\frac{0.186}{365})^{365}-C=C(1.2043)-C=C(0.2043)

The effective annual rate is 20.43%

(d)  Continuously

I=Ce^{0.186}-C=C(1.2044)-C=C(0.2044)

The effective annual rate is 20.44%

3 0
2 years ago
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