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vova2212 [387]
4 years ago
13

Factorise using identity 4y^2 - 12yz+9z^2​

Mathematics
1 answer:
Andrew [12]4 years ago
8 0

Step-by-step explanation:

<u>I</u><u>d</u><u>e</u><u>n</u><u>t</u><u>i</u><u>t</u><u>y</u><u> </u><u>u</u><u>s</u><u>e</u><u>d</u><u> </u> :

\bold{ ({y}^{2} +   {z}^{2})  =  {y}^{2}  + 2yz +  {z}^{2}  }

\implies \:  {(2y)}^{2}  - 2.2y.3z +  {(3z)}^{2}

so we got :

y = 2

z = 3

{ \pink{ \bold{ \boxed{answer = (2y + 3z) {}^{2} }}}}

<u> </u>

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