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Ad libitum [116K]
2 years ago
7

I'm quite confused with the racetrack principle and need help on this problem. . . Suppose that f(t) is continuous and twice-dif

ferentiable for t>= 0. Further suppose f''(t) >= 3 for all t>= 0 and f(0) = f'(0) = 0.. . Using the Racetrack Principle, what linear function g(t) can we prove is less than f'(t) (for t>= 0)? . g(t) = . . Then, also using the Racetrack Principle, what quadratic function h(t) can we prove is less than than f(t) (for t>= 0)? . h(t) = .
Mathematics
1 answer:
Hunter-Best [27]2 years ago
6 0

Race track principle says that if two functions are equal at <span>t=0</span>, then the one which has a greater derivative will be greater.

In this case we're comparing <span><span>f′</span>(t)</span> and <span><span>g′</span>(t)</span>. So we make sure that <span>g(0)=<span>f′</span>(0)</span> and that <span><span>f′′</span>(t)≥<span>g′</span>(t)

</span>


<span>g(t)=at+b</span>


Since it is a line.
<span><span>g′</span>(t)=a</span>


<span><span>f′′</span>(t)≥3≥<span>g′</span>(t)⟹3≥a</span>

So let <span>a=3</span>.

<span><span>f′</span>(0)=0=g(0)=3(0)+b⟹b=0


</span>So that means
<span>g(t)=3t

</span>Do something similar for <span>h(t)</span><span> starting with
</span><span>h(t)=a<span>t2</span>+bt+c

</span><span>h(0)=f(0)⟹c=0

</span>

So

<span>h</span><span>(</span><span>t</span><span>)</span><span>=</span><span>a</span><span>t2</span><span>+</span><span>b</span><span>t</span>

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25/30 + 27/30 = 52/30 = 1 22/30 = 1 11/15 Your answer is A

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Write the pair of fractions as a pair of fractions with a common denominater 3/10 1/2
Serggg [28]

Answer:

3/10 and 5/10

Step-by-step explanation:

1/2 = 5/10

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2 years ago
NEED HELP ASAP!!! WILL MARK BRAINLIEST!!!!!!
Svetach [21]

Step-by-step explanation:

3×3=9. 3 faces so 9×3=27

10×3=30. 4 faces so 30×4=120

6×3=18. 2 faces so 18×2= 36

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120+135=255

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answer =318

6 0
3 years ago
Find the y intercepts of 3x^2+24x-51. quadratic formula
julia-pushkina [17]
  • Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, starting with the y-intercept. To find the y-intercept, set the x variable to zero and solve as such:

y=3*0^2+24*0-51\\y=0+0-51\\y=-51

<u>Your y-intercept is (0,-51).</u>

Next, using our equation plug the appropriate values into the quadratic formula:

x=\frac{-24\pm \sqrt{24^2-4*3*(-54)}}{2*3}

Next, solve the multiplications and exponent:

x=\frac{-24\pm \sqrt{576-(-648)}}{6}\\\\x=\frac{-24\pm \sqrt{576+648}}{6}

Next, solve the addition:

x=\frac{-24\pm \sqrt{1224}}{6}

Now, simplify the radical using the product rule of radicals as such:

  • Product Rule of Radicals: √ab = √a × √b

√1224 = √12 × √102 = √2 × √6 × √6 × √17 = 6 × √2 × √17 = 6√34

x=\frac{-24\pm 6\sqrt{34}}{6}

Next, divide:

x=-4\pm \sqrt{34}

<u>The exact values of your x-intercepts are (-4 + √34, 0) and (-4 - √34, 0).</u>

Now to find the approximate values, solve this twice: once with the + symbol and once with the - symbol:

x=-4+ \sqrt{34},-4- \sqrt{34}\\x\approx 1.83, -9.83

<u>The approximate values of your x-intercepts (rounded to the hundredths) are (1.83,0) and (-9.83,0).</u>

5 0
3 years ago
Given: If you live in Orlando, then you live in Florida.
____ [38]

Answer:

The law of detachment and syllogism is valid here

Explanation:

The law of detachment and syllogism is associated with inductive reasoning. This law states that a conclusion is valid if the premise or hypothesis is valid, therefore if a then b. In others a results in b.

The law of detachment is denoted

[(a→b)∧a]→b

The law of syllogism derives from the law of detachment. Syllogism says that if a results in b and b results in c, then a results in c. In other words since a causes b and b causes c, then if a then c.

It is denoted

[(a→b)∧(b→c)]→(a→c)

In the above example, given: If you live in Orlando, then you live in Florida

Morgan does not live in Orlando, therefore it is concluded that he does not live in Florida

5 0
3 years ago
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