Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
to find the volume of a cylinder
V=π x r^2 x h
now since we want the whole figure were going to add up the two heights to get one height number 4ft + 5ft = 9ft
V= 3.14 x 3^2ft x 9ft
V= 3.14 x 9ft^2 x 9ft
V= 254.34
i tried my best and this is what i know
~batmans wife dun dun dun...
First row is 3 cookies for every $1, proportional, and Table to the right
Second row is 3 more cookies than donuts, non-proportional, and the Table on the left
I beleive it is a because both variable could change
The answer would be 6 weeks.
First, you do 44 divided by 4 to get 11 kg per week. Now you divide 66 by 11 to get 6 weeks.