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3 years ago

Can you help me(×+5) (4x-3)=0

Mathematics

1 answer:

Gemiola [76]3 years ago

6 0

sry my mistake wrong quesrion

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The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin

irakobra [83]

Answer:

$Y = 441$

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

$X^2 \alpha \frac{1}{\sqrt Y} \alpha M$

Convert the variation to an equation; we have

$X^2 = \frac{KM}{\sqrt Y}$

<em>Where K is the constant of variation;</em>

When M = 27; Y = 16; X = 9, the expression becomes

$9^2 = \frac{K * 27}{\sqrt{16}}$

This gives

$81 = \frac{k * 27}{4}$

Make K the subject of formula

$K = \frac{81* 4}{27}$

$K = \frac{324}{27}$

$K = 12$

Solving for Y when M = 7 and X = 2

Recall that $X^2 = \frac{KM}{\sqrt Y}$

Substitute values for K, M and X

$2^2 = \frac{12 * 7}{\sqrt{Y}}$

$4 = \frac{84}{\sqrt{Y}}$

Take square of both sides

$4^2 = (\frac{84}{\sqrt{Y}})^2$

$16 = \frac{7056}{Y}$

Make Y the subject of formula

$Y = \frac{7056}{16}$

$Y = 441$

3 0

3 years ago

Find the polar coordinate of each point 1. (4,0) 2. (3,4) 3. (2,-2)

Rama09 [41]

Hello,

4+0j=4(cos 0+j*sin 0)

3+4j=√5(cos 53.1301...°+j*sin 53.130102...)

2-2j=2√2(cos 45°-j*sin 45°)

3 0

4 years ago

Mark: 1.00

katrin [286]

×find the product of (6×+7y)and (5×-3y)

8 0

3 years ago

Find the product. If the result is negative, enter "-". If the result is positive, enter "+". -7(- a2 ) 2 ( -b3 ).

m_a_m_a [10]

Answer:

The product is positive, thus it is $\bold{+7a^4b^3}$

Step-by-step explanation:

The full question in proper notation is:

"Find the product. If the result is negative, enter "-". If the result is positive, enter "+".

$-7(-a^2)^2(-b^3)$ "

We have to work with it using Order of operations know as well as PEMDAS, thus expression inside parenthesis go first and exponents.

On this expression we have to work with exponents

$(-a^2)^2 = (-a^2)(-a^2) =a^4$

Thus we get

$-7(-a^2)^2(-b^3)=-7a^4(-b^3)$

Lastly we can work with multiplication and remembering that the multiplication of two negative signs becomes positive.

$-7(-a^2)^2(-b^3)=7a^4b^3$

So the final simplified expression is $\bold{7a^4b^3}$

5 0

3 years ago

Read 2 more answers

Please help ill give brainliest

maks197457 [2]

Answer:

divide by -3 and reverse it

Step-by-step explanation:

Trust me I got u fam

3 0

3 years ago

Read 2 more answers