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irinina [24]
3 years ago
10

Can you help me(×+5) (4x-3)=0

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

sry my mistake wrong quesrion

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Read a frequency graph help please!
Nana76 [90]

Answer:

No

Step-by-step explanation:

jan-44

feb-84

mar-72

apr-96

may-52

jun-26

mean=(44+84+72+96+52+26)/6=62.3<65

The answer  is no

7 0
3 years ago
I need help on 1 pleased
nikitadnepr [17]
You add 386 +193 them multiple 4
5 0
2 years ago
If the graph of y = lxl is translated so that the point (1, 1) is moved to (1.4), what is the equation of the new graph?
Fittoniya [83]

Answer:

y = |x| + 3.

Step-by-step explanation:

The movement of  the y value from 1 to 4 is  a translation  of 3 units upwards.

The graph  is y = |x| + 3.

7 0
2 years ago
2a + 4b + c =5 <br> x =-2 <br><br> a - 4b = -6<br> y=1
cricket20 [7]
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10 [2] b-c=15 [3] a-2b+c=-5 Equations Simplified or Rearranged :<span><span>  [1] 2a + c = -10 </span><span>  [2] - c + b = 15 </span><span>  [3] a + c - 2b = -5 </span></span>Solve by Substitution :

// Solve equation [3] for the variable  c  
 

<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable  c  in equation [1]

<span><span>  [1] 2a + (-a +2?-5) = -10 </span><span>  [1] a = -5 </span></span>

// Plug this in for variable  c  in equation [2]

<span><span>  [2] - (-? +2b-5) + b = 15 </span><span>  [2] - b = 10 </span></span>

// Solve equation [2] for the variable  ?  
 

<span> [2] ? = b + 10 </span>

// Plug this in for variable  ?  in equation [1]

<span><span>  [1] (? +10) = -5 </span><span>  [1] 0 = -15 => NO solution </span></span><span>No solution</span>
3 0
2 years ago
Select the basic integration formula you can use to find the indefinite integral.
kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C

Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
3 years ago
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