There are <em><u>25 danishes </u></em>contain cream filling
<h3>Further explanation</h3>
The percent is a number that shows a comparison of the number 100 or can be called per hundred (symbol%)
Formula used:

Fractions either proper or mixed (consisting of numerators and denominators) or decimal forms
The percentage can be expressed as a decimal by moving the decimal point two places to the left
One way to convert proper fractions to percent forms is by multiplying the fraction by 100% or By changing the denominator to 100 because percent is the percent. Multiply the numerator and denominator with the same number
35% from Several trays of danishes are filled with cream
There are four (4) trays
18 danishes on each tray

- 35% are filled with cream

Round up to<em><u> </u></em><em><u>25 danishes</u></em>
<h3>Learn more</h3>
find the percent
brainly.com/question/12541026
Convert 156000 to percentage
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The percent
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Keywords : cream filling, danishes, trays, breakfast
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Answer: Your welcome the answer is in the attached Image.
Step-by-step explanation: mark me brainliest.
Doing the same onee i need help!!
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Answer:
P = 2(n - 6) + 2(n^2 - 8)
Step-by-step explanation:
Remembering that Area = Length times Width, we factor the given function
A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:
A = n^3 - 6n^2 - 8n + 48 factors as follows:
A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)
We can label '(n - 6)' "width" and '(n^2 - 8'
length.
Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:
P = 2(n - 6) + 2(n^2 - 8)
Answer:
1.778 times more or 16/9 times more
Step-by-step explanation:
Given:
- Mirror 1: D_1 = 8''
- Mirror 2: D_2 = 6"
Find:
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?
Solution:
- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:
LGP ∝ A
- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:
A ∝ D^2
- Hence, LGP ∝ D^2
- Now compare the two diameters given:
LGP_1 ∝ (D_1)^2
LGP ∝ (D_2)^2
- Take a ratio of both:
LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2
- Plug in the values:
LGP_1/LGP_2 ∝ (8)^2 / (6)^2
- Compute: LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more