Evaluate using distributive property -7/3*5/9+13/3+4/9*-7/3
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Answer:
Step-by-step explanation:
Garrett achieves a field goal is independent of each kick. Hence X no of kicks is binomial with p = 0.83, and q =0.17
No of trials 3
Hence X can take values as 0 ,1,2,3 and
, r=0,1,2,3
Using the above we obtain prob distribution as
X 0 1 2 3
P(X) 0.0049 0.0720 0.3513 0.5718
P(X>=2) =P(X=2,3,4) =0.9231
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2) Z value for company A =
Z value for company B =
From z value probablility is more for company A as
P(Z>-2.22) >P(Z>2.89)