Question 1:
F(x) and g(x) are like variables, just plug into the equation.
f(x) + g(x) = (x + 6) + (12x - 7)
x+6+12x-7 = 13x-1
Question 2: f(3) + g(-1)
You plug in the x-values into the equation, and then take the answer and add them together.
f(3) = 3+4
g(-1) = 12(-1)-6
f(3) = 7
g(-1) = -18
7 + (-18) = -11
Question 3:
This is similar to question 1, plug in the variables and simplify.
9x - (7x+3)
Remember to distribute the "-"
9x - 7x - 3
2x - 3
You can’t technically solve it because there’s no question
The scenario can be described using a piecewise function like:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
<h3>
When the value exists but the limit does not?</h3>
Remember that the limit only exists if the limit from left and the limit from the right give the same value.
Then, we can just define a piecewise function of the form:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
Clearly, this is not a continuous function.
Notice that:

So the limits from left and right are different, then:

Does not exist.
If you want to learn more about limits:
brainly.com/question/5313449
#SPJ1
Answer:

Step-by-step explanation:
General arithmetic sequence formula: 
where
= first term, and d = common difference.
The first term is -8
And the common difference appears to be - 7 as 7 is subtracted to get to the next term. Ex. -8 - 7 = -15, -15 - 7 = - 22 and so on.
To get the explicit formula of the sequence we simply plug in the values of a1 and d the general arithmetic sequence formula
General formula: 
We have
and d = -7
So the formula to find the nth term would be

THE PROBABILITY IS likely to be one half half of the slice of the pizza