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4 years ago

Which of the following shows the two patterns?

Mathematics

1 answer:

alexdok [17]4 years ago

3 0

Answer:

pls be more specific

Step-by-step explanation:

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Select the correct answer. Each statement describes a transformation of the graph of

Sever21 [200]

Answer:

The correct answer is d.

Step-by-step explanation:

Let's solve each answer and see which one matches.

Note that in each case, you simply add or subtract from x inside the radical to move left or right respectively. Similarly, just add or subtract to the full expression to move up or down respectively. Doing so we get:

a) $f(x) = \sqrt[3]{x + 7} + 3$

b) $f(x) = \sqrt[3]{x - 3} - 7$

c) $f(x) = \sqrt[3]{x - 3} + 7$

d) $f(x) = \sqrt[3]{x - 7} + 3$

So d is the correct answer.

6 0

3 years ago

Solve this step by step

Kaylis [27]

Step-by-step explanation:

the formula to calculate a circumference is

$x \times \pi$

(consider x as the diameter)

so I'll be noting the circumference as C alongside the circle's ranking

$ca = 6 \times 22 \div 7 \\ = 44 \div 7$

$cb = 7 \times 22 \div 7 \\ = 154 \div 7 \\ = 22$

$cc \: = 4 \times 22 \div 7 \\ = 88 \div 7$

hope I helped

8 0

3 years ago

Stephany is inviting 3 friends to a party. If each friend will get 7 cookies and each box has 10 cookies, how many boxes does St

Aleksandr [31]

Answer:

3 boxex hope that helps. yea. thats the answer

7 0

3 years ago

If the divisor is 4 and the quotient is 8, what is the dividend ?

kolbaska11 [484]

<h3>If the divisor is 4 and the quotient is 8, Then, dividend is 32</h3>

<em><u>Solution:</u></em>

Given that,

Divisor = 4

Quotient = 8

To find: dividend

We know that,

$Dividend \div divisor = quotient$

Therefore,

$Dividend \div 4 = 8\\\\Dividend \times \frac{1}{4} = 8\\\\Dividend = 8 \times 4\\\\Dividend = 32$

Thus, dividend is 32

3 0

3 years ago

Find the coordinates of the midpoint of VW with endpoint V(-2,-6) and W(x+2,y+3)

mariarad [96]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ V(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-6})\qquad W(\stackrel{x_2}{x+2}~,~\stackrel{y_2}{y+3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{(x+2)-2}{2}~~,~~\cfrac{(y+3)-6}{2} \right)\implies \left( \cfrac{x}{2}~~,~~\cfrac{y-3}{2} \right)$

7 0

3 years ago