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2 years ago

Amy buys two shirts. One shirt costs $12.95 and the other costs $15.98. How much money does Amy spend altogether

Mathematics

2 answers:

pshichka [43]2 years ago

5 0

She spent 28.93 in total

shtirl [24]2 years ago

4 0

Answer:

$28.93

Step-by-step explanation:

12.95+15.98 = $28.93

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Determine whether the following is a statistical question.

-BARSIC- [3]

Answer:

Yes, the given question is a statistical question.

Step-by-step explanation:

Given: statement is "What is the typical height of dog kennels at Keita's Kennels?"

To check: whether the given statement is a statistical question

Solution:

A statistical question is one for which you will generally get more than one answer.

For example "What's the age of the students in your school?" is a statistical question but "What's your age?" is not a statistical question.

The given statement "What is the typical height of dog kennels at Keita's Kennels?" has a single answer only, so the given question is statistical

7 0

3 years ago

Match the two numbers with their least common multiple

Darya [45]

8 - 8, 16, 24, 32, 40, 48

4 - 4, 8, 12, 16,

So the LCM of 8 and 4 are C) 8

8 - 8, 16, 24, 32, 40, 48

6 - 6, 12, 18, 24, 30

So the LCM of 8 and 6 are A) 24

8 - 8, 16, 24, 32, 40, 48

10 - 10, 20, 30, 40, 50

The LCM of 8 and 10 are B) 40

Hope this Helps!!

3 0

2 years ago

Geometry help I need the statements and reasons

GenaCL600 [577]

O is the midpoint of Reason: Defintiin of a midpoint

7 0

2 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago

Hi help rn plss this is a system of equations question

otez555 [7]

Answer:

x=6, y=2

Step-by-step explanation:

8 0

2 years ago