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hram777 [196]
3 years ago
6

In the polynomial 4x3 + 5x2 − 12, what is the coefficient of the x2 term?

Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

5

Step-by-step explanation:

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A cylinder has a height of 12 inches and a radius of 1.5 inches. What is its voulme? Round your answer to the nearest tenth. Use
USPshnik [31]

Find the area of the top, which is a circle.

Area of a circle = pi x r^2

Area = 3.14 x 1.5^2 = 7.065

Now for the volume multiply the area of the top by the height:

7.065 x 12 = 84.78 cubic inches

Round to the nearest tenth: 84.8 cubic inches

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3 years ago
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One evening, Mr. Smith, Sam, and Sydney went to see the Myrtle Beach Pelicans’ Game. They each bought a ticket and a hat that co
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You can't answer this question without knowing the total amount of money they all had in total.

3 0
3 years ago
Find the distance between the two points.<br> (-6, – 7), (0,0)
Elden [556K]

Answer:

√85

Step-by-step explanation:

for this, you will probably need to draw a graph. Plot the points, and then you will notice that you can draw a triangle with one side being the x-axis ( go on to (-6,0) then drop down unitll you hit the point (-6;-7)

// use the pythagoream theorem to find the length

the distance of the leg on the x-axis is 6  (calculate 0-(-6))

the distance of the leg that is dropping down is -7 (calculate 0-(-7))

then we have 2 legs and need to find the hypotenuse.

Pythagorean theorem a^2 + b^2 = c^2

substitute :

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8 0
3 years ago
The square root of a number is between 8 and 9 .Which of these could be that number?
Kay [80]
<u>The answer is C</u>.  This is because the square of 8 is 64 and the square of 9 is 81.  The only number in between those choices is C; 71.

Hope this helps :)

(mind giving me brainliest answer? it helps!)
3 0
4 years ago
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Let g(x) = 2x and h(x) = x^2 + 4. Find the value.(g o h) (0)a) 4b) 8c) 0d) 16
Paul [167]
\begin{gathered} \text{Given} \\ g(x)=2x \\ h(x)=x^2+4 \end{gathered}

Solve for (g o h)(x)

\begin{gathered} (g\circ f)(x)=g\big(f(x)\big) \\ (g\circ f)(x)=g(x^2+4) \\ (g\circ f)(x)=2(x^2+4) \\ (g\circ f)(x)=2x^2+8 \end{gathered}

Next substitute x = 0

\begin{gathered} (g\circ f)(x)=2x^2+8 \\ (g\circ f)(0)=2(0)^2+8 \\ (g\circ f)(0)=8 \end{gathered}\text{Therefore, }(g\circ f)(0)=8

5 0
2 years ago
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