Let u=x^3
the original equation becomes: u^2-9u+8=0
factor this quadratic equation: (u-8)(u-1)=0
u=8, or u=1
that means x^3=8 or x^3=1
x=2 x=1
Answer:
Step-by-step explanation:
4252 rounded is 4000.
Explanation:
When it says "significant number", we assume to round to the nearest thousand. To do this, we look at the hundredths place. If the number in the hundredths place is 1-4, we keep the 4000. If the number is from 1-5, we round up to 5000. Since the hundredths place is 2, we round down to 4000.
Answer:
dI/dt= -0,000127 A/s
Step-by-step explanation:
From Ohm's Law we have V = IR . deriving on both sides of equality
dV/dt = dI/dt R + I dR/dt . clearing, dI/dt = 1/R (dV/dt - I dR/dt)
replacing by the values of the statement
dI/dt = 1/400Ω (-0,05 V/s - 0,02 A 0,04Ω/s) . making calculations
dI/dt = -0,0508V/s / 400Ω = -0,000127 V/sΩ. simplifying the units
dI/dt = -0,000127 A/s
