4
<span> ∑ [100(−4)n−1]
n=1
Once again, since this is summation notation:
</span>Start at the number on the bottom. Plug in that number to the equation on the right, plug in the next number into the equation on the right, and so on, until you get to the number on top. Plug in that final number, and after you get the solution, add all the solutions you have all together.
<span>One thing though: <span>the bottom number cannot be bigger than the number on top.
</span></span>
n=1; 100 x (-4) x (1) - 1 = -401
n=2; 100 x (-4) x (2) - 1 = -801
n=3; 100 x (-4) x (3) - 1 = -12001
n=4; 100 x (-4) x (4) - 1 = - 16001
-401-801-12001-16001 = -29204
V - (0,0) U- (4,3) T - (2,0)
you just find the spot that point is at!
Answer: bro you have to submit a picture or some more information baceuse nobody will be able to answer your question with only one number (45)
Step-by-step explanation:
Kellin's median credit score = 733
Natasha's median credit score = 699
Edward's median credit score = 782
Lisa's median credit score = 792
d. Lisa because she has the highest median score.
Let's handle this case by case.
Clearly, there's no way both children can be girls. There are then two cases:
Case 1: Two boys. In this case, we have 13 possibilities: the first is born on a Tuesday and the second is not (that's 6 possibilities, six ways to choose the day for the second boy), the first is not born on a Tuesday and the second is (6 more possibilities, same logic), and both are born on a Tuesday (1 final possibility), for a total of 13 possibilities with this case.
Case 2: A boy and a girl. In this case, there are 14 possibilities: The first is a boy born on a Tuesday and the second is a girl born on any day (7 possibilities, again choosing the day of the week. We are counting possibilities by days of the week, so we must be consistent here.), or the first is a girl born any day and the second is a boy born on a Tuesday (7 possibilities).
We're trying to find the probability of case 1 occurring given that case 1 or case 2 occurs. As there's 13+14=27 ways for either case to occur, we have a 13/27 probability that case 1 is the one that occurred.