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3 years ago

Fill in the blank.

Mathematics

1 answer:

Marrrta [24]3 years ago

7 0

Question:

Fill in the blank.

23 x 6 = (20 + 3) * 6

23 x 6 = _ + (3x6)

Options

20 * 6

20 * 3

20 * 5

Answer:

20 * 6

Step-by-step explanation:

Given

Expression 1: 23 * 6 = (20 + 3) * 6

Expression 2: 23 * 6 = __ + (3 * 6)

Required

Fill in the blank

From Expression 1

23 * 6 = (20 + 3)*6

Using Distributive Property; The expression becomes

23 * 6 = 20 * 6 + 3 * 6

23 * 6 = (20 * 6) + (3 * 6)

By Comparing this with expression 2

23 * 6 = __ + (3 * 6)

The blank position is occupied by 20 * 6.

Hence, the correct option that fills the missing blank correctly is 20 * 6

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Tony is mailing packages. Each small package costs him $2.80 to send. Each large package costs him $3.60. How much will it cost

Natasha_Volkova [10]

Answer:

The answer is $33.6

Step-by-step explanation:

Each small package costs him $2.80

3 small packages will cost him 3 x $2.80 = $8.4

Each large package costs him $3.60

7 large packages will cost 7 x $3.60 = $25.2

Cost to send 3 small packages and 7 large packages = $8.4 + $25.2

= $33.6

6 0

3 years ago

In a particular faculty 60% of students are men and 40% are women. In a random sample of 50 students what is the probability tha

zimovet [89]

Answer:

a) The expected value is given by:

$E(X) = np = 50*0.4 = 20$

and the variance is given by:

$Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12$

b) $P(X>25)= 1-P(X\leq 25)$

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

$P(X>25)= 1-P(X\leq 25)=0.0573$

c) 1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

$X \sim N(\mu = 20 , \sigma= 3.464)$

d) $P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z$

e) $P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)$

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=50, p=0.4)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

The expected value is given by:

$E(X) = np = 50*0.4 = 20$

and the variance is given by:

$Var(X) =np(1-p) = 50*0.4*(1-0.4) = 12$

Part b

For this case we want to find this probability:

$P(X>25)= 1-P(X\leq 25)$

And we can find this probability with the following Excel code:

=1-BINOM.DIST(25,50,0.4,TRUE)

And we got:

$P(X>25)= 1-P(X\leq 25)=0.0573$

Part c

1) Random sample (assumed)

2) np= 50*0.4= 20 >10

n(1-p) =50*0.6= 30>10

3) Independence (assumed)

Since the 3 conditions are satisfied we can use the normal approximation:

$X \sim N(\mu = 20 , \sigma= 3.464)$

Part d

We want this probability:

$P(X>25) = 1-P(Z< \frac{25-20}{3.464}) = 1-P(z$

Part e

For this case we use the continuity correction and we have this:

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)$

$P(X>25)= P(X>25.5) = 1-P(X \leq 25.5)= 1-P(Z$

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Answer:

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2nd equation is ???

Step-by-step explanation:

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Answer:

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