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Zepler [3.9K]
3 years ago
12

The area of the parallelogram is 399 square units. What is the height of the parallelogram?

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0

Answer: The answer is 19.

Step-by-step explanation:

I took the quiz, and the correct answer to the question is 19.

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Which function will have a y-intercept at –1 and an amplitude of 2?
Angelina_Jolie [31]

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

h(x)=A\sin (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

The general form of cosine function

h(x)=A\cos (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

In function, f(x)=-\sin x-1

Amplitude : |A|=1

y-intercept : -1

In function, f(x)=-2\sin x-1

Amplitude : |A|=2

y-intercept : -1

In function, f(x)=-\cos x

Amplitude : |A|=1

y-intercept : 0

In function, f(x)=-2\cos x-1

Amplitude : |A|=2

y-intercept : -1

Therefore, the correct options are B and D.

4 0
3 years ago
Read 2 more answers
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
What is the value of P for the following triangular prism?
Zolol [24]
Pretty sure its 36 (not sure) i keep getting 36.6 cm
3 0
3 years ago
wade has a test score of 77% on his first test and 65% on his second test. what must he score on a third test to have an average
zubka84 [21]

Answer:

faillll

Step-by-step explanation:

6 0
3 years ago
The circumference of a circle is 19 pi meters. What is the radius in meters?
Sliva [168]

Answer:

<h3>Area of a circle in terms of radius:</h3>

Area = π·r^2 = 3.14·9.5^2 = 283.5 square meters(*)

Area of a circle in terms of diameter:

Area = π·(d/2)^2 = 3.14·(19/2)^2 = 3.14·(9.5)^2 = 283.5 square meters(*)

Area of a circle in terms of circumference:

Area = C^2/4π = 59.69^2/4π = 3562.9/(4·3.14) = 3562.9/12.56 = 283.5 square meters(*)

(*) 283.52873698648 meters, exactly or limited to the precision of this calculator (13 decimal places).

Note: for simplicity, the operations above were rounded to 2 decimal places and π was rounded to 3.14.

Step-by-step explanation:

Hope it is helpful....

8 0
3 years ago
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