Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
Answer:
A)14 Units is the answer for this question
but check it
The answer is 2x(2x²+x+1).
When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)
9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0
This gives us
4x³+2x²+2x
Each of these is divisible by 2, and each has an x, so we factor those out:
2x( )
4x³/2x = 2x²:
2x(2x² )
2x²/2x=x:
2x(2x²+x )
2x/2x = 1:
2x(2x²+x+1)
The answer is 63. 9 times 7 is 63
The answer would be 15.7142857143
You can get the answer by calculating (5/7) × 22
