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BlackZzzverrR [31]

3 years ago

6

The value of the digit in the hundreds place in the number 234,865 is 1/10 the value of the digit in the thousands place of whic

h number? A. 873,445
B. 508,372
C. 682,067
D. 135,387

1 answer:

Lilit [14]3 years ago

3 0

B. 508,372 because I think it is in my head

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Find the midpoint of the line segment

strojnjashka [21]

Answer:

midpoint (5,4)

Step-by-step explanation:

The midpoint(M) of a segment with endpoints (x₁ , y₁) and ( x₂, y₂) is

where x₁ = 2 and x₂ = 8

y₁ = 0 and y₂ = 8

M = $\frac{x_1 + x_2}{2} ,\frac{y_1 + y_2}{2}$

M = $\frac{2 + 8}{2} ,\frac{0 + 8}{2}$

M = 5 , 4

5 0

3 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒

$P(E)=\frac{4}{36}=\frac{1}{9}$ ⇒

$P(E)=\frac{1}{9}$

Finally we are going to define the event $F$ ⇒

$F$ : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

$F$ = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = $P(A,B)$

We define the conditional probability as

$P(A|B)=\frac{P(A,B)}{P(B)}$ with $P(B)>0$

We need to find $P(F|E)$ therefore we can apply the conditional probability equation :

$P(F|E)=\frac{P(F,E)}{P(E)}$ (I)

We calculate $P(E)=\frac{1}{9}$ at the beginning of the question. We only need $P(F,E)$ .

Looking at the sets $E$ and $F$ we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

$P(F,E)=\frac{1}{36}$

Replacing both probabilities calculated in (I) :

$P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25$

We find out that $P(F|E)=\frac{1}{4}=0.25$

6 0

3 years ago

A student has some $1 and $5 bills in his wallet. He has a total of 15 bills that are worth $35. How many of each type of bil

Bumek [7]

He has 5 $5 bills and 10 $1 bills because 5x5=25 and 10x1=10. to check the answer you add 25+10=35.

5 0

3 years ago

Students received grades with or - (example B ). Of all students who received one or more plus grades, 92% were undergraduates a

MrMuchimi

Answer:

The probability that a student is an undergraduate student, given that the student received a plus grade is 0.92

Step-by-step explanation:

The conditional probability of an event <em>B</em> given that another event <em>A</em> has already occurred is:

$P(B|A)=\frac{P(A\cap B)}{P(A)}$

Denote the events as follows:

<em>X</em> = a students is a graduate

<em>Y </em>= a students is a under-graduate

+ = a student received one or more plus grades

- = a student received one or more minus grades

Consider the tree diagram below.

According to the tree diagram, the probability that a student is an undergraduate student, given that the student received a plus grade is:

P (+ | Y) = 0.92

Thus, the probability that a student is an undergraduate student, given that the student received a plus grade is 0.92.

8 0

3 years ago

The rate at which sand is poured into a bag is modeled by the function r given by r(t)=15t−2t2, where r(t) is measured in millil

balu736 [363]

Answer:

35 mililiters

Step-by-step explanation:

Given

$r(t) = 15t - 2t^2$

Required

Accumulated amount from t = 0 to 2

This implies that, we substitute the values of t from 0 to 2 in the function

$r(0) = 15*0 - 2*0^2= 0$

$r(1) = 15*1 - 2*1^2= 13$

$r(2) = 15*2 - 2*2^2= 22$

The accumulated sand (r) is:

$t = r(0) + r(1) + r(2)$

$r = 0 + 13 + 22$

$r = 35$

6 0

3 years ago