Answer:
0
Step-by-step explanation:
Answer:
Step-by-step explanation:
let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.
The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:
P(B/C) = P(B∩C)/P(C)
Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.
So, P(C) is calculated as:
P(C) = 18 / 30 = 0.6
Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.
At the same way, P(B∩C) is equal to:
P(B∩C) = 6 / 30 = 0.2
Finally, P(B/C) is equal to:
P(B/C) = 0.2/0.6 = 0.3333
-3.9 ÷ 1.3 = -3
good luck :)
To find the mean of something you are finding the average, so add all the times they were late to school. Then divide by the number of numbers you had to add. You will have your answer by doing that. What it means to interpret your answer is to explain it.
1. multiply the number of absences by the number of students.
2. Add the number of absences
3. divide by the number of students.
Speed: 30mi/sec
Seconds in one minute: 60
Seconds in 6 minute: 60 x 6 = 360 seconds
take the speed of 30miles / seconds and times it with 360, and you get a total distant traveled: 10800 miles