Answer:
missing side: 133 cm
Explanation:
Provided <u>2 length sides</u> and <u>one angle</u> also need to find <u>one missing side</u>.
So, use cosine rule:
⇒ a² = b² + c² - 2bc cos(A)
<u>Insert values</u>
⇒ g² = 166² + 147² - 2(166)(147) cos(50)
⇒ g² = 17794.3935
⇒ g = √17794.3935
⇒ g = 133.3956
⇒ g = 133 (rounded to nearest whole number)
Answer:
12100
Step-by-step explanation:
If the number B of federally insured banks could be approximated by B ( t ) = − 329.4 t + 13747 from 1985 to 2007 where t = 0 correspond to year 1985
In order to determine the amount of federally insured banks that were there in 1990, we will first calculate the year range from initial time 1985 till 1990
The amount of time during this period is 5years. Substituting t = 5 into the modeled equation will give;
B ( t ) = − 329.4 t + 13747
B(5) = -329.4(5) + 13747
B(5) = -1647+13747
B(5) = 12100
This shows that there will be 12100 federally insured banks are there in the year 1990.
Answer:
1.42 hours
Step-by-step explanation:
In this case we must take into account that the speed would be to fill a pool for a time, that this case is in hours, therefore it would be like this:
1/5 for the first pipe
1/2 for the second pipe
Now, we will use both at the same time, therefore:
1/5 + 1/2 = 1 / x
0.7 = 1 / x
x = 1 / 0.7
x = 1.42
That is to say that if we use both we will take a total of 1.42 hours
*see attachement for the triangles given
Answer:
PQ = 6.8
Step-by-step explanation:
Corresponding sides of similar shapes or figures are proportional to each other. Since ∆LMN ~ ∆OPQ, the ratio of their corresponding sides would therefore be equal. Thus:
LN/OQ = MN/PQ
LN = 5
OQ = 17
MN = 2
PQ = ?
Plug in the values
5/17 = 2/PQ
Cross multiply
5*PQ = 2*17
5*PQ = 34
PQ = 34/5
PQ = 6.8
Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!