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iragen [17]
2 years ago
10

PLEASE HELP!!! 100 points (make sure to show work and be correct)

Mathematics
2 answers:
myrzilka [38]2 years ago
6 0

Answer:

1. B (15,100) & E (18,120)

2. A (3,9)

Step-by-step explanation:

Equation:

y = mx + c

m = (80-20)/(12-3) = 60/9 = 20/3

c = 0

y = 20x/3

(15,100)

100 = 20(15)/2

100 = 100

(18,120)

120 = (20×18)/2

120 = 120

2.

y = 3x

Where y is the amount and x is the no. of bracelet

This is a proportional relationship

From the options, only A satisfies the relationship

tresset_1 [31]2 years ago
5 0

Answer:

1. B and E

2. B

Step-by-step explanation:

1. Looking at the line, let's try to establish a relationship between x and y. Take one point (12, 80) and divide y by x:

80 / 12 = 20 / 3

Similarly, if we take (3, 20), we get the same relationship:

20 / 3 = 20 / 3

That means we need to select an ordered pair that follows this relationship:

A. (14, 100)  ⇒  100 / 14 = 50 / 7 --- wrong

B. (15, 100)  ⇒  100 / 15 = 20 / 3 --- correct

C. (16, 100)  ⇒  100 / 16 = 25 / 4 --- wrong

D. (16, 120)  ⇒  120 / 16 = 15 / 2 --- wrong

E. (18, 120)  ⇒  120 / 18 = 20 / 3 --- correct

The possible answers are B and E.

2. Let's say Maya sells b bracelets. That means that she makes 3 * b = 3b dollars for these b bracelets. Look at the answer choices to see which one will have 3 in the x-coordinate and a multiple of 3 in the y-coordinate:

A. (3, 5)  ⇒  5 isn't a multiple of 3, so wrong.

B. (3, 9)  ⇒  3 is the x-coordinate and 9 = 3 * 3, so this is correct.

C. (3, 7)  ⇒  7 isn't a multiple of 3, so wrong.

D. (2, 3)  ⇒  3 isn't even the x-coordinate, so wrong.

The correct answer is thus B.

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if the equation 2x^2+ bx+ 5=0 has no real solutions, which of the following must be true A. b^2 &lt; 10 B. b^2&gt; 10 C. b^240​
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Answer:

C. b²< 40

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What is the value of a for the following circle in general form?<br> x2 + y² + ax + by+c=0
motikmotik

Answer:

Step-by-step explanation:

x2+y2+ax+by+c=0

Step 1: Add -by to both sides.

ax+by+x2+y2+c+−by=0+−by

ax+x2+y2+c=−by

Step 2: Add -x^2 to both sides.

ax+x2+y2+c+−x2=−by+−x2

ax+y2+c=−bax+y2+c+−y2=−by−x2+−y2

ax+c=−by−x2−y2

Step 4: Add -c to both sides.

ax+c+−c=−by−x2−y2+−c

ax=−by−x2−y2−c

Step 5: Divide both sides by x.

ax

x

=

−by−x2−y2−c

x

a=

−by−x2−y2−c

x

y−x2

6 0
2 years ago
Read 2 more answers
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