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ANTONII [103]
3 years ago
9

Please help! Especially with the steps!

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer:a)680cu.ft

b)180cu.ft

Hope this helped you...

Step-by-step explanation:


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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
2 years ago
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can someone do my iready please its due in 4 hours 3 ill give 20 points for it!!!!!! PLEASEEEE (*´◒`*)
Dima020 [189]

Answer:

YAYA

Step-by-step explanation:

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2 years ago
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the
vfiekz [6]

Answer:

Probability that the result is a multiple of 4 or a multiple of 3=  0.428

Step-by-step explanation:

The spinner is divided into 14 equal areas.

Probability of an event=\frac{number of favourable outcomes}{total number of outcomes}

For favourable events,result should be a multiple of 3 or 4.

All the possible outcomes are=1,2,3,4,5,6,7,8,9,10,11,12,13,14

  • Multiples of 3=3,6,9,12
  • Multiples of 4=4,8,12

Hence the favourable outcomes are=3,4,6,8,9,12

Number of favourable outcomes=6

Total number of outcomes=14

Probability=\frac{6}{14}

                 =0.428

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2 years ago
What is one fourth divided by 2
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One fourth is the same as 1/4 1. 2 ÷ 4. 1 Reciprocal 1. 1 × 4. 2 Multiply normally. 1/8=answer
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choice (A) is correct

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