Answer:
21.75 m
Explanation:
t = Time taken for the car to slow down = 0.75 s
u = Initial velocity = 50 m/s
v = Final velocity = 8 m/s
s = Displacement
a = Acceleration
Equation of motion

Acceleration is -56 m/s²

The distance covered in the 0.75 seconds is 21.75 m
-7 2/3 or -23 / 3
Hope this helped :)
Answer:
1000 N
Explanation:
An impulse results in a change of momentum
FΔt = mΔv
F = 0.001 kg(1000 - 0) m/s / 0.001 s = 1000 N
Answer:
The combined velocity is 8.61 m/s.
Explanation:
Given that,
The mass of a truck, m = 2800 kg
Initial speed of truck, u = 12 m/s
The mass of a car, m' = 1100 kg
Initial speed of the car, u' = 0
We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

So, the combined velocity is 8.61 m/s.