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lesya [120]
3 years ago
12

Which sediments typically make up the C horizon?

Physics
2 answers:
Nastasia [14]3 years ago
5 0
B) sand, silt, and clay!
AlekseyPX3 years ago
4 0
Sand,Silt and clay is the right option.
Enjoy !
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How many atoms of Oxygen (O) are in 3CO2
ikadub [295]

Answer:

2

Explanation:

BRAINLIEST?? AND THANK ME LATER!!! HOPE THIS HELPED!!!

5 0
3 years ago
Manufacturers sometimes use science to make foods more nutritious. Food manufacturers can make reduced fat potato chips, besides
pogonyaev
All of the choices are correct.
5 0
4 years ago
Read 2 more answers
At this rate, what fraction of its mass would io lose in 4. 5 billion years?.
Pie

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Given that:

Io loses about a ton (1000 kilograms) of sulfur dioxide per second to Jupiter's magnetosphere.

In 4.5 billion years, amount of mass lost = 1000 kg/s * (4.5 * 10⁹ * 365 * 60 60 * 24) = 1.41912 * 10¹⁷ kg.

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

Find out more on Equation at: brainly.com/question/13763238

4 0
2 years ago
A new interstate highway is being built with a design speed of 120 km/h. For one of the horizontal curves, the radius (measured
nikklg [1K]

Answer:

28.79%

Explanation:

Given

Design Speed, V = 120km/h = 33.33m/s

Radius, R = 300m

Side Friction, Fs = 0.09

Gravitational Constant = 9.8m/s²

Using the following formula, we'll solve the required rate of superelevation.

e + Fs = V²/gR where e = rate

e = V²/gR - Fs

e = (33.33)²/(9.8 * 300) - 0.09

e = 0.287853367346938

e = 28.79%

Hence, the required rate of superelevation for the curve is calculated as 28.79%

4 0
4 years ago
Can someone explain it with steps?
Anton [14]

Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

=15\times0.4\\\\=6m

The car stopped before hitting the animal by 1 m

Distance travelled during deceleration is 21-6-1=14m

Hence by v^2=u^2+2as

We have

0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2

Option C is the correct answer

5 0
3 years ago
Read 2 more answers
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