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Crank
3 years ago
8

Wafa drove 420 kilometers using 18 liters of gas. At this rate, how many liters of gas would she need to drive 357 kilometers?

Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

15.3 litres

Step-by-step explanation:

You can do this many different ways, but this is how i did it:

1) I'm going to find how much gas it takes to travel just 1 km.

So, to drive for 1 km, I only need 18/420 litres of gas.

<em>*you can solve this, but you'll just get a really long decimal, so i find it easier just to keep it as a fraction until i'm at the end of solving. </em>

2) Now times the amount of petrol it takes to travel 1 km by 357, to find the final answer.

18/420 x 357 = 15.3 litres

Hope that helped : )

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Mr. Alexander had a negative bank account balance of -$50. He went out to dinner, and spent $23.73. The balance in Mr. Alexander
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Answer:

-$73.73

Step-by-step explanation:

To get this answer, we must subtract 23.73 from -50, as Mr. Alexander is losing money by spending. Once we subtract, we get -73.73 dollars.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
Pls help me that would be great
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3 years ago
The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man
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Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

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We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2

So, the area of the floor space is equal to 5.83 sq yards.

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