Ask question

Ask question

All categories

erma4kov [3.2K]

2 years ago

10

Para ampliar uma sala quadrada, foram acrescentados 4 metros em seu comprimento e 2 metros em sua largura, conforme a figura. Qu

al polinômio apresenta a área dessa sala após a ampliação? *
a) x² + 4x + 8
b) x² + 6x + 8
c) x² + 2x + 8
d) x² + 8
e) 2x + 6

1 answer:

ollegr [7]2 years ago

3 0

Answer:

b) $x^2 + 6x + 8$

Step-by-step explanation:

Para ampliar la habitación cuadrada, se agregaron 4 metros de largo y 2 metros de ancho, como se muestra en la figura.

Deje que la longitud y el ancho de la habitación antes de la expansión sean x.

La nueva longitud de la sala es (x + 4).

El nuevo ancho de la sala es (x + 2).

La nueva área de la sala será:

$(x + 4)(x + 2)\\x^2 + 2x + 4x + 8\\x^2 + 6x + 8\\\\$

Esa es la nueva área de la habitación.

You might be interested in

I dont understand<br> help please!!!

shutvik [7]

Answer: I

Why?
(A-p)/p= I

6 0

2 years ago

3/8 x 2/6 x 4/8 x 5/12

Evgesh-ka [11]

Answer:

$\frac{5}{192}$

Step-by-step explanation:

$\frac{3}{8} * \frac{2}{6} * \frac{4}{8} * \frac{5}{12}$

Multiply all numerators

3 * 2 * 4 * 5 = 6 * 20 = 120

Multiply all denominators

8 * 6 * 8 * 12 = 48 * 96 = 4,608

$\frac{120}{4608}$

Simplify

$\frac{5}{192}$

Hope this helps :)

3 0

2 years ago

PLEASE HELP! FAST!

kumpel [21]

So it would by 4/10. simplify that and its B. 2/5

7 0

2 years ago

Read 2 more answers

What is the standard form of a quadratic with a root of <br><img src="https://tex.z-dn.net/?f=2i%20%5Csqrt%7B3%7D%20" id="TexFor

kari74 [83]

Step-by-step explanation:

$2\sqrt{ - 3}$

5 0

2 years ago

SIMPLIFY THE EXPRESSION... PLEASE HELP :(

erastova [34]

remember $\frac{\frac{a}{b}}{\frac{c}{d}}=(\frac{a}{b})(\frac{d}{c})=\frac{ad}{bc}$

try to combine fractions in numerator and denomenator

numerator: $\frac{1}{x}+\frac{2}{y}$

make common denom

multiply left one by $\frac{y}{y}$ and right one by $\frac{x^2}{x^2}$

$\frac{y}{yx^2}+\frac{2x^2}{yx^2}=\frac{2x^2+y}{yx^2}$

denomenator

$\frac{5}{x}-\frac{6}{y^2}$

make common denom

multiply left one by $\frac{y^2}{y^2}$ and right one by $\frac{x}{x}$

$\frac{5y^2}{xy^2}-\frac{6x}{xy^2}=\frac{5y^2-6x}{xy^2}$

combining we get

$\frac{\frac{1}{x^2}+\frac{2}{y}}{\frac{5}{x}-\frac{6}{y^2}}=$

$\frac{\frac{2x^2+y}{yx^2}}{\frac{-6x+5y^2}{xy^2}}=$

$(\frac{2x^2+y}{yx^2})(\frac{xy^2}{-6x+5y^2})=$

$\frac{2x^3y^2+xy^3}{-6x^3y+5x^2y^3}=$

$(\frac{2x^2y+y^2}{-6x^2+5xy})(\frac{xy}{xy})=$

$(\frac{2x^2y+y^2}{-6x^2+5xy})(1)=$

$\frac{2x^2y+y^2}{-6x^2+5xy}$

8 0

2 years ago

Read 2 more answers