We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
It’s b pls brainiest me have a Good day
Answer:
p = - 2
Step-by-step explanation:
Given
n = 2 + 6m ← substitute m = -
into the expression
n = 2 + 6(-
) = 2 - 3 = - 1
Thus
p =
=
= - 2
5x + 5/4 = x - 3/9
5•x + 5/4 = x - 3/9
144x = -57
x = -19
48
≈ -0.395833