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2 years ago

9

Jen had fifty dollars in her wallet. Mom gave her some money. Now she has 100 dollars. How much money did her mom give her? Writ

e this phrase in algebraic equations and try solving.

1 answer:

pantera1 [17]2 years ago

4 0

Answer:

$50

Step-by-step explanation:

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The ages of Sohail, Afzal and Bilal are 17, 16 and 12 respectively. If the age of Aslam also included the average of the ages is

vichka [17]

Sohail=17

afzal=16

Bilal=12

Aslam=16+5=21

4 0

2 years ago

I need help to these questions. Convert these fractions to a decimal 7/8 , 4 3/8. Thanks

ehidna [41]

Simple...

you have: $\frac{7}{8}$ and $4 \frac{3}{8}$

Now, the first one is easy just divide it...

$\frac{7}{8} =0.875$

Now....

$4 \frac{3}{8}$ needs to be converted...

Multiply the whole number*denominator...

4*8=32

Now add the numerator....

32+3=35

Now use the original denominator...

$\frac{35}{8}$

Now divide...

$\frac{35}{8}=4.375
$

Thus, your answer.

7 0

2 years ago

Read 2 more answers

Use the graph that shows the solution to

Inessa05 [86]

Answer:

Step-by-step explanation:

c

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3 years ago

Find the quadratic function that fits the following data. which one function fits.

Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c$

We get the system of three equations:

$\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.$

Subtract these equations:

$\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.$

From the first equation

$b=-120a$

Substitute it into the second equation:

$5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5$

So,

$2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25$

The quadratic function is

$y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25$

4 0

3 years ago

Chester Boles reviewed his credit card's monthly statement. It shows a $2,376.10 previous balance and this month's new purchases

ss7ja [257]

Initial balance, I = $2376.10 .

Total amount of purchase made, A = $( 875.22+65.75+45.22+21.23 ) = $1007.42 .

Total amount credit, c = $875.22 .

Fine, f = $45.30 .

Another purchase, $a=\dfrac{2376.10\times 2.5}{100}=\$ 59.4025$ .

So, balance left is :

B = I - A - f - a + c

B = 2376.10 - 1007.42 - 45.30 - 59.4025 + 875.22

B = $2139.1975

Hence, this is the required solution.

4 0

3 years ago