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Natali5045456 [20]
3 years ago
14

Please help please !!!!!!!!!!!!!!!

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

Linear

The function is linear since the graph of it would be a straight line. You can tell this by looking at the equation since there are no squares, roots, division, etc. that would make the line stray.


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Krissa wants to buy some acrylic paint. She needs 47 mL of black, 59 mL of yellow, and 48 mL of brown. Each bottle holds 55 mL o
Snowcat [4.5K]
B and C are the right answers since you don't want to mix colors
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3 years ago
I need help asap plz I will mark branlist promise
anygoal [31]

Assuming none of the factors is zero, if an odd number of the factors of a multiplication problem have negative signs, then the product will be negative. Otherwise, the product is positive.

Assuming the dividend of a division problem is non-zero, the quotient wil be negative if the signs of the dividend and divisor are differnt. Otherwise the quotient is positive.

In short, if a multiplication or division problem involves an odd number of minus signs, the result will be negative. Otherwise, the result is positive.

5 0
3 years ago
Landen spent L hours at the beach last weekend. Matéo spent 15% fewer hours at the beach than Landen did
fenix001 [56]

Answer: B, D, and E

0.85L

or

L-0.15L

or

L(1-0.15)

or

L - \frac{15}{100}L

L - \frac{3}{20}L

Step-by-step explanation:

L is the number of hours Landen spent at the beach. Mateo spent 15% less time. This means he spent 85% of it. So 0.85 times L. We can also calculate it by subtracting the difference between the two kids. - 15%. 15% is 0.15L or \frac{15}{100}L. We subtract by L-0.15L or as L - \frac{15}{100}L. This fraction can simplify to L - \frac{3}{20}L

4 0
2 years ago
Read 2 more answers
Evaluate the integral Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is d
algol13

You want to find the volume inside the hemisphere x^2+y^2+z^2=4 (i.e. inside the sphere but above the plane z=0) and outside the cylinder x^2+y^2=1. Call this region R.

In cylindrical coordinates, we have

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_1^2\int_0^{\sqrt{4-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

\displaystyle=2\pi\int_1^2 r\sqrt{4-r^2}\,\mathrm dr

\displaystyle=-\pi\int_3^0\sqrt u\,\mathrm du

(where u=4-r^2)

\displaystyle=\pi\int_0^3\sqrt u\,\mathrm du

=\dfrac{2\pi}3u^{3/2}\bigg|_0^3=2\sqrt3\,\pi

7 0
3 years ago
Please HEEEELLPPP!!!!
inn [45]

Answer:

No

Step-by-step explanation:

Because, m'lady that is kind of a slope, so it can't relate to the equation, it would be something else-

                                            -kid

6 0
3 years ago
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