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3 years ago

ANSWER NEEDED NOW!!!!!!!!!!!

Mathematics

1 answer:

KonstantinChe [14]3 years ago

4 0

Answer:

Step-by-step explanation:

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A cylinder has a height h, and a radius (3h-2)

tekilochka [14]

Answer:

$V= 4\pi (9h^2 -12h + 4)$

Step-by-step explanation:

Given

Shape: Cylinder

$Radius = 3h - 2$

$Height = h$

$Base\ Area = \pi (3h - 2)^2$

Required

Simplify the volume

The volume is calculated as:

$Volume = Base\ Area * Height$

Substitute values for Base Area and Height

$V= \pi(3h-2)^2*h$

Expand the bracket

$V= \pi(3h-2)(3h-2)*h$

Open brackets

$V= \pi (9h^2 -6h - 6h + 4) *h$

$V= \pi (9h^2 -12h + 4) *h$

$V= 4\pi (9h^2 -12h + 4)$

6 0

3 years ago

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

4 years ago

In seven days they washed 285.38 pounds of towels and 353.47 pounds of sheets. about how many pounds of laundry did they wash ea

Temka [501]

In seven days they washed a total of 638.85 pounds of laundry. This means each day they washed about 91.26 pounds of laundry.

3 0

3 years ago

Read 2 more answers

Find the slope of the line passing through (-8,6) and (6,6)

frosja888 [35]

Answer:

Step-by-step explanation:

6-6 equals 0 and -8 minus 6 equals -14 and 0 divided by equals 0

8 0

4 years ago

7. In each case, write an equation that models the situation described. a) An antique is purchased for $5000 in 1990. It appreci

balandron [24]

A) A= 5000 x .0325 ( 31)
A= 5,037.50

.0325 = 3.25%
31 years 2021-1990 = 31

3 0

3 years ago

ANSWER NEEDED NOW!!!!!!!!!!!​

ANSWER NEEDED NOW!!!!!!!!!!!