The Solution:
Given:
Center = (0,0)
Point A = (-5,2) being a point on the circle.
We are required to check if point P = (2,-5) is on the circle.
Solving the given problem graphically, we have:
From the above graph, it is clear that point P(2,-5) is a point on the circle.
Mean = $52
median = $53
no mode
range = 63 - 40 = $23
A. The
y-intercept (b) of a linear equation is obtained when x = 0. Therefore from the
given table,
y - intercept
= 8
Since at
time zero the displacement is 8 ft, this means that the horse was already
outside the barn initially.
B. The
average rate of change of the function represents the slope of the linear
equation (m). This can be calculated using the formula:
average rate
of change = m = (y2 – y1) / (x2 – x1)
m = (158 –
58) / (3 – 1)
m = 50
<span>C. Since we have determine the y-intercept and
the slope, we can formulate the linear equation:</span>
y = m x + b
y = 50 x + 8
The domain
is the value of x. When y = 508, x is equivalent to
508 = 50 x +
8
<span>x = 10 hrs</span>
Answer:
2210.6 
Step-by-step explanation:
Volume of a cylinder is 
they want to the nearest tenth, so ≈ 2210.6
The puppy runs a distance of D) 18 - 19 meters in one lap.
Step-by-step explanation:
Step 1; It is given that the leash measures 3 meters long. He runs pulling the leash as much as he can creating circles. Even though he keeps pulling, the leash will remain at a constant length of 3 meters. So we need to calculate the perimeter of the circle.
Step 2; The perimeter of any given circle is 2π times the radius. The radius of this circle is equal to 3 meters.
Perimeter of the circle = 2π × r = 2 × 3.1415 × 3 meters = 18.85 meters.
So the puppy runs a distance of 18.85 meters in a lap.
