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3 years ago

Yes yes - drop the answer or ill drop ur ip

Mathematics

1 answer:

nikitadnepr [17]3 years ago

5 0

It’s d = 2 I don’t feel like showing my work I’ll just give you this answer

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Need an answer for question 7 HURRY PLEASE 20 POINTS

Andrei [34K]

Answer:

2x^2 = 6x - 5.

-x^2 - 10x = 34.

These have only complex roots/

Step-by-step explanation:

3x^2 - 5x = -8

3x^2 - 5x + 8 = 0

There are complex roots if the discriminant 9b^2 - 4ac) is negative.

Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160

This is positive so the roots are real.

2x^2 = 6x - 5

2x^2 - 6x + 5 = 0

D = (-6)^2 - 4*2*5 = 36 - 40 = -4

So this has no real roots only complex ones.

12x = 9x^2 + 4

9x^2 - 12x + 4 = 0

D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.

- Real roots.

-x^2 - 10x = 34

x^2 + 10x + 34 = 0

D = (10)^2 - 4*1*34 = 100 - 136 = -36.

No real roots = only complex roots.

7 0

3 years ago

Please help

son4ous [18]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In detail explain how to multiply in binomial of (5x-7 (2x-1) in foil method

Nesterboy [21]

Step-by-step explanation:

First

Outer

Inner

Last

First- 5x*2x=10x^2

Outer-5x*-1= -5x

Inner--7*2x= -14x

Last- -7*-1= 7

10x^2-5x-14x+7

you can simplify it further however thats the answer

4 0

2 years ago

A metal washer has an outer diameter of 14mm and an inner diameter of 6mm.Use the value of 3.14 for the to find the area of the

Elena L [17]

Answer:

502.4 mm^2

Step-by-step explanation:

First find the area of the larger circle, and then that of the smaller one.

Then subtract the latter (2nd) area from the first.

larger circle area smaller circle area

------------------------- ---------------------------

3.14(14 mm)^2 3.14(6 mm)^ 2

This comes out to 3.14[14^2 - 6^2] mm^ 2 = 3.14[196 - 36] mm^2, or

3.14(160 mm^2) = 502.4 mm^2

The area of the metal washer is 502.4 mm^2.

3 0

2 years ago

What number must you add to complete the square?<br> x^2 + 2x = -1

Andru [333]

$\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

6 0

3 years ago

Read 2 more answers