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3 years ago

PLZ HELP I WILL GIVE BRAINLIEST.....

Mathematics

1 answer:

poizon [28]3 years ago

8 0

Answer:

1) -16

2) +3

Step-by-step explanation:

1) below represents negative sign

2) increase means posivie sign

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PLEASSSSSSSSSEEEEEEEEEEEE IS NOT A SCAMMM" I JUST NEED HELP

emmainna [20.7K]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which inequality hs the graph shown below. (will mark you brainliest)

zvonat [6]

Answer:

y < 2x-3

Step-by-step explanation:

First you graph the -3, and the slope is 2 so you go up 2 and over 1. Since y is less than 2x-3, you shade the right region.

6 0

3 years ago

The sides of a quadrilateral are x,x+3,x+4,x+5. it’s perimeter is 52, find the lengths of the sides

wariber [46]

Answer: 10 , 13 , 14 , 15

Step-by-step explanation:

To find the perimeter of a quadrilateral , we will add all its side , that is

Perimeter = x + x + 3 + x + 4 + x + 5

That is

52 = x + x + 3 + x + 4 + x + 5

52 = 4x + 12

subtract 12 from both sides

40 = 4x

divide through by 4

x = 10

therefore , the lengths of the sides are

10 , 10+3 , 10 + 4 , 10 + 5 , that is

10 , 13 , 14 , 15

4 0

3 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

3 years ago

Ash invests £200 and gets 3% interest per year. How much will she have after 5 years?

Taya2010 [7]

Answer:

£231.85

Step-by-step explanation:

→ Work out the decimal multiplier

( 3 + 100 ) ÷ 100 = 1.03

→ Multiply the initial investment by the multiplier raised to the power of years

200 × ( 1.03 )⁵ = £231.85

6 0

2 years ago