110 horses can be found in one day with 44 bales of hay. If each horse needs 2/5 bales of hay each day, just convert 2/5 into a decimal (0.4) and divide 44 by 0.4 to get 110. (That's a lot of horses!)
You would have to watch 62 3D movies to make an annual pass the less expensive option out of the two of them.
62x25 = 1550
I think the answer is 1/23
Please tell me if I'm wrong.
B
You would divide 45 mm/15mm to get 3. Multiply 3 by 27 to get 81 mm.
Firstly, let's create a function of f(t) where t represents the time that has past, and f(t) represents the amount of rainwater. We know that when t=1, then f(t)=10, and t=2 then f(t)=15. So, let's take that and analyze it:
(1,10)
(2,15)
m = (15-10)/(2-1) = 5
y-intercept = 5
∴ f(t) = 5t+5
Now we just evaluate t for 10:
f(10) = (5*10)+5
f(10) = 55
