Answer:
(a) k = C + 273.15, F = 1.8(k - 273.15) + 32
(b) k = 296.15
(c) 25 celcius is greater than 300 kelvis.
Step-by-step explanation:
(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.
C = k - 273.15
C + 273.15 = k
k = C + 273.15
F = 1.8(k - 273.15) + 32
(b) for this one you have to substitute in the previous equation and solve for k.
23 = k - 273.15
k = 23 + 273.15
k = 296.15
(c) you have to convert either kelvins to celcius or celcius to kelvins.
C = k - 273.15
C = 300 - 273.15
C = 26.85
So 25 celcius is greater than 300 kelvis.
Answer:
mean=71
Step-by-step explanation:
Mean x¯¯¯x¯
71
Median x˜x~
72
Mode
64, 83, 79, 38, 81, 90, 59, 93, 70, 73, 71, 51
Range
55
Minimum
38
Maximum
93
Count n
12
Sum
852
Quartiles
Quartiles:
Q1 --> 61.5
Q2 --> 72
Q3 --> 82
Interquartile
Range IQR
20.5
Outliers
none
The known endpoint is P = (-16,0)
Let Q = (x,y) be the other endpoint. It is unknown for now.
Looking at the x coordinates of P and Q, we see that they are -16 and x respectively. Adding these values up gives -16+x. Dividing that result by 2 gives (-16+x)/2. This result is exactly equal to the midpoint x coordinate, which is the x coordinate of M (0).
So we have this equation (-16+x)/2 = 0. Let's solve for x
(-16+x)/2 = 0
2*(-16+x)/2 = 2*0
-16+x = 0
x-16 = 0
x-16+16 = 0+16
x = 16
Therefore the x coordinate of point Q is 16.
------------------------------------
Let's do something similar for the y coordinates.
The y coordinates of P and Q are 0 and y respectively. Add them up and divided by 2, then set the result equal to -16 (y coordinate of midpoint M) getting this equation (0+y)/2 = -16
Solve for y
(0+y)/2 = -16
y/2 = -16
2*y/2 = 2*(-16)
y = -32
The y coordinate of point Q is -32
------------------------------------
The point Q goes from (x,y) to (16, -32)
Final Answer: (16, -32)
Answer: C.
Step-by-step explanation:
You notice how the number goes from
3.50 to 3.62 to <u>3.49 </u>to 3.88
hThe 3.49 is out of place. Thus ruining the order of least to greatest.
