The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
r = 2.39 and C=2πr=2·π·2.39≈14.99997
Step-by-step explanation:
Using the formula
C=2πr
Solving for r=C 2π=15
2·π≈2.38732
and then u round up the 7 told the 8 to go up.
2.39
Answer:
-14
Step-by-step explanation:
a·b = |a|×|b|×cos(angle between them)
= 4×7×(-1/2)
= -14
Answer:
B.) 
Step-by-step explanation:
use the slope rule

Fill in values

Simplify

Simplify further

Done.