Let t, h, b represent the weighs of tail, head, and body, respectively.
t = 4 . . . . given
h = t + b/2 . . . . the head weighs as much as the tail and half the body
b/2 = h + t . . . . half the body weighs as much as the head and tail
_____
Substituting for b/2 in the second equation using the expression in the third equation, we have
... h = t + (h + t)
Subtracting h from both sides gives
... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.
Conclusion: there's no solution to the problem given here.
I believe the answer is 120. 3 5/6 turns into 3.833 when turned into a decimal. 3.833 would round up to 4 which is the nearest whole number. 34 3/7 would turn into 34.4285 as a decimal which turns into 30 when rounded to the nearest ten.
First plug in g(x) into f(x)
F((g(x))=2(2x+3)
And now you plug in -8
F(g(-8))=2(-16+3)
F(g(-8))=2(-13)
F(g(-8))=-26
Independent, x-coordinate, input, domain.
Dependent, y-coordinate, output, range.
Domain: {0.5, 1, 4, 6, 8}
Range: {1, 1.5, 10, 12, 18}
Answer:
YTM = 5.45%
Step-by-step explanation:
Here, we are interested in calculating the yield to maturity.
Mathematically;
Annual coupon=1000*4.3%=43
YTM=[Annual coupon+(Face value-Present value)/time to maturity]/(Face value+Present value)/2
=[43+(1000-870)/18]/(1000+870)2
=5.45%