Answer:
8
Step-by-step explanation:
Answer:
I may not be correct, depending on what you were taught, but it would be...
17/30
Step-by-step explanation:
(2/5×6/6)+(1/6×5/5)
12/30 + 5/30
17/30
keep in mind you don't add the denominators at all ( the numbers at the bottom half of the fraction)
One is significantly fatter than the other and has more friction
Since it is indicated that the sum of three consecutive odd integers is at most 216 and not exactly 216, the largest possible value of one of these integers is 73. The answer for this question would be option C. 69, 71, and 73 are the consecutive odd integers. Hope this answers your question.
