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oksian1 [2.3K]
3 years ago
10

How would I use a number line?

Mathematics
2 answers:
Scrat [10]3 years ago
6 0
1. u find the solution to the problem (-8)
2. Make
a # line. 
3. Put the # on the # line.
Zolol [24]3 years ago
3 0
All you have to do is distrubute which would give you the anwser of -8 and then all you do is draw you a numberline with 0 in the middle and negative numbers on the left side of 0 and on the right side put your positive numbers and them put your point by -8 and then you will be done.
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Find the value of x in each case. Give reasons to justify your solutions! e L, M ∈ KN
Greeley [361]

Answer:

X=36

Step-by-step explanation:

3x+72=180

3x=180-72

3x=108

x=36

8 0
3 years ago
Last year, the average math SAT score for students at one school was 475. The headmaster introduced new teaching methods hoping
Debora [2.8K]
I would argue that it does due to that if it increased, it's either from a 30% chance that nothing changed or that the teachers did it. Since 100-30=70, there's a 70 percent chance that the teaching effect did work!
4 0
3 years ago
Read 2 more answers
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
(Giving Brainliest♡)
frutty [35]

Answer:

15

Step-by-step explanation:

Hi there! :)

If you created 5 circles cut into thirds, you would create 15 1/3 pieces.

You can also use the KCF method to solve this!

7 0
3 years ago
What is the average rate of change for this quadratic function for the interval
stealth61 [152]
<h3>Answer:   -4  (choice B)</h3>

==========================================================

Explanation:

The table says that when x = 1, the output is y = -2.

So the point (1, -2) is on the parabola.

The table also says that point (3, -10) is on the parabola. We're focusing on this because x = 3 is the other endpoint.

Find the slope of the line through those two points. The slope here is the same as the average rate of change.

m = (y2 - y1)/(x2 - x1)

m = (-10 - (-2))/(3 - 1)

m = (-10 + 2)/(3 - 1)

m = -8/2

m = -4 is the slope, and therefore, the average rate of change from x = 1 to x = 3.

6 0
3 years ago
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