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3 years ago

How would I use a number line?

Mathematics

2 answers:

Scrat [10]3 years ago

6 0

1. u find the solution to the problem (-8)
2. Make a # line.
3. Put the # on the # line.

Zolol [24]3 years ago

3 0

All you have to do is distrubute which would give you the anwser of -8 and then all you do is draw you a numberline with 0 in the middle and negative numbers on the left side of 0 and on the right side put your positive numbers and them put your point by -8 and then you will be done.

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3 years ago

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eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

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3 years ago

Write an equation (any form) for the quadratic graphed below. Y=

Licemer1 [7]

Answer:

y = -2x^2 - 4x - 1

Step-by-step explanation:

We can see that the graph passes through (-2, -1), (-1, 1) and (0, -1).

Let's solve

ax^2 + bx + c = y

a(-2)^2 + b(-2) + c = -1

4a - 2b + c = -1

a(-1)^2 + b(-1) + c = 1

a - b + c = 1

a0^2 + b0 + c = -1

c = -1

we got c = -1 so we input it into the other 2

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2a - b = 0

2a = b

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a - b = 2

a = b + 2

Let's input b = 2a

a = 2a + 2

-a = 2

a = -2

b = 2a = 2*(-2) = -4

c = -1

y = -2x^2 - 4x - 1

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3 years ago