Answer:
The range of the graph is:
-3 ≤ y ≤ 3
Hence, option (B) is correct.
Step-by-step explanation:
We know that the range of a function is the set of values of the dependent variable 'y' for which a function is defined.
From the given graph, it is clear that the graph goes down at y=-3 and then goes up to y=3 and then goes down again.
In fact, this indicates that the range of the graph lies between y=-3 to y=3
Therefore, the range of the graph is:
-3 ≤ y ≤ 3
Hence, option (B) is correct.
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
Answer:
The value found is.
sin θ = 0.6
Step-by-step explanation:
We know that the value of cosθ is given -4/5
cosθ = -4/5
First, lets finds the angle θ by taking inverse of cosine of -4/5
θ = cos⁻¹ (-4/5)
θ = 143.13°
Substitute the found θ = 143.13° it in tanθ to see if satisfies the equation tanθ < 0:
tanθ < 0
tan(143.13°) < 0
-0.75 < 0
Hence the equation is satisfied.
Which means that θ is equals to 143.13° and can be used to find sinθ
sinθ = sin 143.13°
sin 143.13° = 0.6
Answer:
yes it is
Step-by-step explanation:
it is quadrilateral
