1) let both have x ,
so putting in eqn ;
4x+0.50 = 9x-3
5x=2.50
x=0.50
therefore both have 50 p in the beginning !!
2) let the number be x
so in eqn;
(x+18)/2=5x
x+18=10x
9x=18
x=2
so the number must be 2 !!
if you have still any problem, comment !!
Answer:
|GH| = 5,7 cm
Step-by-step explanation:
To know |GH|, you first need to find the length of |GD|.
We can calculate |GD| by;
cosG = |GC| / |GD|
<=> |GD| = |GC| / cosG
=> |GD| = 3,9 cm/ 0,62 = 6,33 cm
We now can easily calculate |GH| with the sinus of angle D;
sinD = |GH| / |GD|
<=> |GH| = sinD.|GD|
=> |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm
I hope i did not make a mistake ...
Answer:
Domain: (-∞, ∞) or All Real Numbers
Range: (0, ∞)
Asymptote: y = 0
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Step-by-step explanation:
The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.
The range is from 0 to ∞. This where all values of y are defined.
An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.
The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Angle A would be 10 degrees.
Complementary angles add to 90 degrees.
So 90-80=10
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer