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3 years ago

Point J is located at (-4,4). Select all of the following that are 4 units from point J.

Mathematics

1 answer:

lara [203]3 years ago

4 0

Answer:

<h2><em>All of the above!</em></h2>

Step-by-step explanation:

They all are 4 points away from (-4, 4)..

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<u>Hope this helps.</u>

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Use the coordinates of the labeled point to find the point-slope equation of the line.

LenKa [72]

For this case we have that by definition, the equation of a line of the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It's the slope

$(x_ {0}, y_ {0})$ : It is a point through which the line passes

To find the slope, we need two points through which the line passes, observing the image we have:

$(x_ {1}, y_ {1}): (3, -5)\\(x_ {2}, y_ {2}): (0,4)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {4 - (- 5)} {0-3} = \frac {4 + 5} {-3} = \frac {9} {- 3} = - 3$

Thus, the equation is of the form:

$y-y_ {0} = - 3 (x-x_ {0})$

We choose a point:

$(x_{0}, y_ {0}) :( 3, -5)$

Finally, the equation is:

$y - (- 5) = - 3 (x-3)\\y + 5 = -3 (x-3)$

Answer:

$y + 5 = -3 (x-3)$

Option D

6 0

4 years ago

Read 2 more answers

Find x. Give reasons to justify your solution.

stich3 [128]

Answer:

x = 28

Step-by-step explanation:

If AB and CD are the straight lines, sum all the angles formed at a point lying on this line will be 180°.

m∠COE + m∠EOF + m∠FOB + m∠BOD = 180° [Angles at a point O on line AB]

3x + x + (x + 12) + m∠BOD = 180°

m∠BOD = 180° - (5x + 12)

Similarly, m∠AOD + m∠AOC = 180°

152° + m∠AOC = 180°

m∠AOC = 28°

Since, ∠AOC and ∠BOD are the vertical angles,

m∠AOC = m∠BOD

180° - (5x + 12)° = 28°

5x + 12 = 180 - 28

5x = 140

x = 28

3 0

3 years ago

A manufacturing company is expected to pay a dividend of br. 1.25 per share at the end of the year (D1=br.1.25). The stock sells

Mama L [17]

Answer:

the equilibrium expected growth rate is 6.65%

Step by step Explanation:

We were given stock sold per share of $32.50

Dividend per share =$1.25

Required Return rate = 10.5%

Then we can calculate Percentage of Dividend for share as;

dividend of br. 1.25 per share at the end of the year (D1=br.1.25)

= 1.25×100= 125

Let the dividend percentage = y

stock sold per share × y= 125

125= 32.50y

y = 125/32.50

y= 3.85

y= 3.85*100%

Then the Dividend percentage = 3.85%

Growth rate=(required rate of return -Dividend percentage)

= 10.5 - 3.85 = 6.65

Therefore, the equilibrium expected growth rate is 6.65%

3 0

3 years ago

What can k equal so that 2kx-3k<2x+4+3kx to have no solution

const2013 [10]

Answer: k = -2
solution: 2kx-3k<2x+4+3kx,
-3k-4<2x+3kx-2kx,
-3k-4<(k+2)x
Since this inequality has no solution, k = -2.

3 0

3 years ago

4. What is the system of equations that describes the following graph?

GarryVolchara [31]

Answer:

The system of inequalities is

$y$

$y>0.25x$

Step-by-step explanation:

step 1

Find the equation of the dashed line with negative slope

The line passes through the points

(0,-2) and (-2,0)

Find the slope

$m=(0+2)/(-2-0)=-1$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-1\\b=-2$

substitute

$y=-x-2$

The solution of the inequality is the shaded area below the dashed line

therefore

The equation of the inequality A is

$y$

step 2

Find the equation of the dashed line with positive slope

The line passes through the points

(0,0) and (4,1)

Find the slope

$m=(1-0)/(4-0)=0.25$

Find the equation of the line (direct variation)

$y=kx$

we have

$k=0.25$

substitute

$y=0.25x$

The solution of the inequality is the shaded area above the dashed line

therefore

The equation of the inequality B is

$y>0.25x$

therefore

The system of inequalities is

$y$

$y>0.25x$

4 0

3 years ago