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Anna35 [415]
3 years ago
7

Uhh.i dumb the screenshot is here

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0

Answer:

40

Step-by-step explanation:

Just use a calculator. I didn´t need to. My brother helped me a little

Dominik [7]3 years ago
8 0
The answer is 40 I believe
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You can answer this question by plugging the given values into point-slope form, which is y - y_{1} = m (x - x_{1}). M will represent slope and x_{1} and y_{1} will represent the x and y coordinates.

   y - y_{1} = m (x - x_{1})   Substitute in the values
y - (-5) = 4 (m - 4)   Cancel out the -(-5)
   y + 5 = 4 (m - 4)   Use the Distributive Property
   y + 5 = 4m - 16    Subtract 5 from both sides
       
         y = 4m - 21
 

3 0
3 years ago
What is the formula to find the area of a circle?
VMariaS [17]

Answer:it’s A

Step-by-step explanation:

5 0
3 years ago
Jesse made a model of a mountain range for class. to do this, he bought a cylinder of cardboard and cut it into three cones. eac
aniked [119]
By definition, the volume of the cone is given by:
 V = (1/3) (π) (r ^ 2) (h)
 Substituting values we have:
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 V = (20/3) (π)
 Then, the volume of the cylinder is:
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 Vc = 3 * (20/3) (π)
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the volume of the original cylinder jesse bought is:
 
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4 0
3 years ago
Can someone please help me ASAP ill mark brainlist!!!
kondor19780726 [428]

Answer:

2 2/3

Step-by-step explanation:

8 0
3 years ago
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
kotegsom [21]

Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

4 0
3 years ago
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