For this case, we can model the problem as a triangle with a right angle.
Where,
x, y: lengths of the sides of the triangle
d: hypotenuse of the triangle
We then have the following relationship:

Clearing d we have:
Answer:
A functions that would best model the situation above is:
D square root
The answer is b corresponding angles are supplementary
Pounds is more if you do the math
Y intercept = (0,12)
x intercept = (-2,0)
Y = 1
Using y = mx + c.
Compare to y = 1, y = 0x + 1 ,
We can see that the slope m = 0 and the vertical intercept, c = 1.
For the line perpendicular to y = 1
Condition for perpendicularity m₁m₂ = -1
m₁ = 0, m₂ = ?
0*m₂ = -1
m₂ = -1/0 = Negative Infinite or Infinite
Slope of line perpendicular to y = 1, is = Infinite.