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antoniya [11.8K]
3 years ago
9

If 3, x, y, -9 are in A.P, find the values of x and y.​

Mathematics
1 answer:
Serggg [28]3 years ago
6 0

Answer:

  • x = -1
  • y = -5

Step-by-step explanation:

The common difference (d) can be found using the first and 4th terms:

  a1 = 3

  a4 = a1 +d(4 -1)

  -9 = 3 +3d . . . . . simplify

  -3 = 1 + d . . . . . . divide by 3

  -4 = d . . . . . . . . . subtract 1

Then ...

  x = a1 + d = 3 -4 = -1

  y = x + d = -1 -4 = -5

The values of x and y are -1 and -5, respectively.

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If the outside temperature was 72 yesterday and today is 16 degrees cooler what is today's temperature
Natalija [7]

Answer:

56 degrees Fahrenheit

5 0
3 years ago
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Voltage sags and swells. The power quality of a transformer is measured by the quality of the voltage. Two causes of poor power
zysi [14]

Answer:

a

 z-score = 1.57

b

 z-score_s = -3.36

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  103  

    The  sample mean of  sag is  \= x_1 =  353

     The sample mean of swells is  \= x_2 =  184

    The standard deviation of  sag is  s_1  =  30

     The standard deviation of swells is  s_2  =  25

     The number of swell for a randomly selected transformer is  k  =  100

      The number of sag for a randomly selected transformer is  c  =  400

Generally the z-score for the number of swells is mathematically represented as

     z-score_s = \frac{ k - \= x_2}{s_2}

=>   z-score_s = \frac{ 100- 184}{25}

=>     z-score_s = -3.36

       

Generally the z-score for the number of sags is mathematically represented as    

      z-score = \frac{ c - \= x_1}{s_1}

     z-score = \frac{ 400 - 353}{30}

     z-score = 1.57

4 0
3 years ago
If 4 Maths books are selected from 6 different Maths different English books, how many ways can the seven om Maths books and 3 E
alexgriva [62]

Answer:

Please see the answer below

Step-by-step explanation:

a. Since there’s no restrictions .Therefore , the number of ways = 7!*150 = 756000

b. The number of ways such that the 4 math books remain together

The pattern is as follows:  MMMMEEE, EMMMMEE, EEMMMME, and EEEMMMM

Where M = Math’s Book and E= English Book.  

Number of ways = 4!*8!*4*150= 86400 ways.

c. The number of ways such that  math book is at the beginning of the shelf

The number of ways = 6!*4*150 = 432000

d. The number of ways such that  math and English books alternate

The number of ways = 150*4!*3! =2160 ways

e.  The number of ways such that math is at the beginning and an English book is in the middle of the shelf. The number of ways = 4*3*5!*150 =216000 ways.

6 0
3 years ago
I don't know how to explain it but please help!
Wittaler [7]

Answer:

required answer. is 1/x³

7 0
3 years ago
HELPPPPPPPPPPPPPPPPPPP!!!
Zielflug [23.3K]

Answer:

x=-4

Step-by-step explanation:

(x+4) ^ (1/3) + (2x+8) ^ (1/3) = 0

Subtract (x+4) ^ (1/3) from each side

(x+4) ^ (1/3) - (x+4) ^ (1/3)+ (2x+8) ^ (1/3) = -(x+4) ^ (1/3)

(2x+8) ^ (1/3) = -(x+4) ^ (1/3)

Cube each side

(2x+8) ^ (1/3) ^3= -(x+4) ^ (1/3)^3

2x+8 = -(x+4)

Distribute the negative sign

2x+8 = -x -4

Add x to each side

2x+8 +x =-x+x-4

3x+8 = -4

Subtract 8 from each side

3x+8-8 =-4-8

3x =-12

Divide by 3

3x/3 = -12/3

x = -4

8 0
3 years ago
Read 2 more answers
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