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miss Akunina [59]
3 years ago
10

students in sixth grade class were asked which team was their favorite. the results are shown in the table. find the ratio of st

udents who preferred the buccaneers to the total number of responses. tigers 35 pathers 45 buccaneers 74 and aviators 52
Mathematics
1 answer:
Serjik [45]3 years ago
8 0
I don't know because I'm not in six grade
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Please help! I’ve been struggling trying to figure out how to start with these two problems.
Vinil7 [7]

Answer:

Step-by-step explanation:

7 0
1 year ago
Can anyone simplify 24q2/8q-3
Morgarella [4.7K]
24q^2 / 8q^-3

lets break this down...
24/8 = 3

q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5

put them together and u get : 3q^5
4 0
3 years ago
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
Can someone please help?
kipiarov [429]
The second one. Hope this helps:)

6,025, 305< 6,026,305< 6,027,305.
3 0
2 years ago
What is the equation of this graph? Please answer this I am soo stuck.
OLEGan [10]

Answer:

y = 8x + 50

Step-by-step explanation:

Use (0,50) and (10,130)

Slope: m = (130-50)/(10-0) = 8

Y-intercept is 50

y = 8x + 50

3 0
2 years ago
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