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3 years ago

I need help ASAP!!!!

Mathematics

2 answers:

melomori [17]3 years ago

8 0

Answer:

Step-by-step explanation:

1/1-2/5

Ede4ka [16]3 years ago

3 0

The answer would be A: 1/5 gallon per minute

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Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

-3.8x - 5.9x = 223.1

katrin2010 [14]

Answer:

x=-23

Step-by-step explanation:

-3.8x-5.9x=223.1

-9.7x=223.1

x=223.1/-9.7

x=-23

5 0

3 years ago

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A random sample of 500 reports an average yearly income of $42,000 with a standard deviation of $1000. An estimate of the parame

Lorico [155]

Answer:

Step-by-step explanation:

Confidence Interval = mean + or - error margin

Mean = 42,000, error margin = width of estimate of the parameter ÷ 2 = 175 ÷ 2 = 87.50

We can be 95% confident that the population mean is 42,000 plus or minus 87.50

8 0

4 years ago

Find s in the parallelogram

adell [148]

Answer:

Step-by-step explanation:

DE=DG

8s-97=3s-22

5s-97=-22

5s=75

s=15

8 0

3 years ago

What is the gcf of 36 and 45

bearhunter [10]

For the values 36 and 45, the GCF = 9

6 0

3 years ago

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