1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinil7 [7]
2 years ago
13

textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year old

s to see if their mean number of daily texts differs from the mean for 18–24 year olds reported by TextRequest.a. State the null and alternative hypotheses we should use to test whether the popu-lation mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.b. Suppose a sample of thirty 25–34 year olds showed a sample mean of 118.6 texts per day. Assume a population standard deviation of 33.17 texts per day and com-pute the p-value.c. With a = .05 as the level of significance, what is your conclusion? d. Repeat the preceding hypothesis test using the critical value approach.d. Repeat the preceding hypothesis test using the critical value approach.
Mathematics
1 answer:
Butoxors [25]2 years ago
4 0

Testing the hypothesis, we have that:

a)

The null hypothesis is: H_0: \mu = 128

The alternative hypothesis is: H_1: \mu \neq 128

b) The p-value of the test is of 0.1212.

c) Since the <u>p-value of the test is of 0.1212 > 0.05</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

d) Since <u>|z| = 1.55 < 1.96</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item a:

At the null hypothesis, we <u>test if the mean is the same</u>, that is, of 128 texts every day, hence:

H_0: \mu = 128

At the alternative hypothesis, we <u>test if the mean is different</u>, that is, different of 128 texts every day, hence:

H_1: \mu \neq 128

Item b:

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

The parameters are:

\overline{x} is the sample mean.

\mu is the value tested at the null hypothesis.

\sigma is the standard deviation of the population.

n is the sample size.

For this problem, the values of the parameters are: \overline{x} = 118.6, \mu = 128, \sigma = 33.17, n = 30

Hence, the value of the test statistic is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{118.6 - 128}{\frac{33.17}{\sqrt{30}}}

z = -1.55

Since we have a two-tailed test, as we are testing if the mean is different of a value, the p-value is P(|z| < 1.55), which is 2 multiplied by the p-value of z = -1.55.

Looking at the z-table, z = -1.55 has a p-value of 0.0606

2(0.0606) = 0.1212

The p-value of the test is of 0.1212.

Item c:

Since the <u>p-value of the test is of 0.1212 > 0.05</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item d:

Using a z-distribution calculator, the critical value for a <u>two-tailed test</u> with <u>95% confidence level</u> is |z| = 1.96.

Since <u>|z| = 1.55 < 1.96</u>, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

A similar problem is given at brainly.com/question/25369247

You might be interested in
if you have a test average of 92 and a standard deviation of 1.8, you generally do well on test. true or false
jeka57 [31]
By most standards yes
3 0
3 years ago
Find the value of x. X=?<br>Volume = 1500 ​
jolli1 [7]

Answer:

x=20

Step-by-step explanation:

Solve the following equation for x:

1500=1/3(15)^{2} x

6 0
2 years ago
Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
3 years ago
-3/7 is equivalent to what other fraction
liubo4ka [24]

Answer:

Step-by-step explanation:

6/14 = -9/21 = -12/28 = -15/35 = -18/42 = -21/49 = -24/56 = -27/63 = -30/70 = -33/77 = -36/84 = -39/91 = -42/98 = -45/105 = -48/112

6 0
3 years ago
28 32 21 22<br> The mean is 24.4 what is the 5th number
Archy [21]
The awnser has to be 26??
6 0
3 years ago
Read 2 more answers
Other questions:
  • There are 6 gallons of distilled water in the science supplies. If 10 students each use an equal amount of distilled water and t
    10·1 answer
  • How many times larger ? Is 1.815x10^3 and 4.975x10^12??????
    13·2 answers
  • I need to understand proofs
    11·1 answer
  • An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.3 m/s. A child on a bridge, 60 m abo
    11·1 answer
  • Solve the following problem: –25 + 37 =
    10·2 answers
  • 4. A glass decoration is made from a cylinder and cone that have the same height and share a base. The cone fits exactly inside
    13·1 answer
  • Which civilization was known to use geometry to construct canals for the transportation of water?
    8·1 answer
  • Brandon wants to buy a new video game for himself. There are 429 different video games on the shelves at Best Buy. Each shelf ca
    9·1 answer
  • Please find the missing side and show your work
    13·1 answer
  • A pole that is 2.6 m tall casts a shadow that is 1.38 m long. At the same time, a nearby building casts a shadow that is 40.75 m
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!