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BabaBlast [244]
3 years ago
5

What is the product of the rational expression

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0
= \cfrac{2 \cdot 5}{(x+1) \cdot 3x} = \cfrac{10}{3x^2+3x}
You might be interested in
Two-thirds of the sum of a number squared and 5 is fourteen
RideAnS [48]

Answer:

2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3

Step-by-step explanation:

Part 1:

Two-thirds ( 2/3 )

of the ( (---) )

sum ( + )

of a number squared ( x^2 ) and 5 ( + 5 )

is fourteen ( = 14 )

Part 2 (Not super confident about):

2/3( x^2 + 5 ) = 14

2/3x^2 + 10/3 = 14

2/3x^2 - 32/3

Hopefully this helps!

Brainliest please?

7 0
2 years ago
PLZ HELP I AM GONNA FAIL JUST EXPLAIN WHAT TO DO ​
Alexxandr [17]
A number cube is a die (singular for dice). List all of the possible outcomes of a die (list numbers of 1 to 6), and next to those numbers, determine if they are even or odd.
8 0
2 years ago
Please help! How do I solve this?
Advocard [28]
m\angle 6=m\angle3\\
8x+7=6x+32\\
2x=25\\
x=12.5\\\\
m\angle 6=8\cdot12.5+7=100+7=107\Rightarrow D

5 0
3 years ago
PLEASE PLEASE HELP
stepan [7]

Answer:


38 divided by 16146.2 = 0.0023534949 then rounded to the nearest hundredth = 0.00

38. divided by 16146.2= The same as that one ^

1614.62 divided by 3.8= 424.9 then rounded you get 424.90

8 0
3 years ago
Keegan is priting and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total p
Damm [24]

Complete question is;

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total profits will be p(x) = -x³ + 4x² + x dollars, in thousands will be earned. How many t-shirts (rounded to the nearest whole number) should he print in order to make maximum profits? What will his profits rounded to the nearest whole dollar be if he prints that number of shirts?

Answer:

Number of t-shirts to make maximum profit = 2790 shirts

Maximum profit = $12,209

Step-by-step explanation:

From the question, we are given that the profit function is;

p(x) = -x³ + 4x² + x

For the maximum value of the profit function,

(dp/dx) = 0 and (d²p/dx²) < 0

Since, p(x) = -x³ + 4x² + x

Then,

(dp/dx) = -3x² + 8x + 1

at maximum point (dp/dx) = 0, thus;

-3x² + 8x + 1 = 0

Solving this using quadratic formula, the roots are;

x = -0.12 or 2.79

Also, (d²p/dx²) = -6x + 8

Now, let's put the roots of x into -6x + 8 and check for maximum value conditon;

at x = -0.12

(d²p/dx²) = -6(0.12) + 8 = 7.28 > 0

At x = 2.79

(d²p/dx²) = -6(2.79) + 8 = -8.74 < 0

Maximum has to be d²p/dx² < 0

So, the one that meets the condition is -8.74 < 0 at x = 2.79

Thus, the maximum of the profit function exists when the number of shirts, x = 2.79 (in thousands) = 2790

Now, the maximum profits that corresponds to this number of t-shirts of 2.79(in thousands) is obtained by putting 2.79 for x in the profit function;

So,

p(2.79) = -(2.79)³ + 4(2.79²) + 2.79

p(x) = -21.7176 + 31.1364 + 2.79

p(x) = 12.2088 (in thousand dollars) ≈ $12,209

6 0
3 years ago
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